Day 4: Ceres Search

Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL

FAQ

  • lwhjp@lemmy.sdf.org
    link
    fedilink
    arrow-up
    5
    ·
    22 days ago

    Haskell

    Popular language this year :)

    I got embarrassingly stuck on this one trying to be clever with list operations. Then I realized I should just use an array…

    import Data.Array.Unboxed (UArray)
    import Data.Array.Unboxed qualified as A
    import Data.Bifunctor
    
    readInput :: String -> UArray (Int, Int) Char
    readInput s =
      let rows = lines s
          n = length rows
       in A.listArray ((1, 1), (n, n)) $ concat rows
    
    s1 `eq` s2 = s1 == s2 || s1 == reverse s2
    
    part1 arr = length $ filter isXmas $ concatMap lines $ A.indices arr
      where
        isXmas ps = all (A.inRange $ A.bounds arr) ps && map (arr A.!) ps `eq` "XMAS"
        lines p = [take 4 $ iterate (bimap (+ di) (+ dj)) p | (di, dj) <- [(1, 0), (0, 1), (1, 1), (1, -1)]]
    
    part2 arr = length $ filter isXmas innerPoints
      where
        innerPoints =
          let ((i1, j1), (i2, j2)) = A.bounds arr
           in [(i, j) | i <- [i1 + 1 .. i2 - 1], j <- [j1 + 1 .. j2 - 1]]
        isXmas p = up p `eq` "MAS" && down p `eq` "MAS"
        up (i, j) = map (arr A.!) [(i + 1, j - 1), (i, j), (i - 1, j + 1)]
        down (i, j) = map (arr A.!) [(i - 1, j - 1), (i, j), (i + 1, j + 1)]
    
    main = do
      input <- readInput <$> readFile "input04"
      print $ part1 input
      print $ part2 input